Kipling, Rudyard

Forma preferată Kipling, Joseph Rudyard
200 _0 $aKipling $bRudyard
299 __ $aKipling, Rudyard
400 _0 $aKipling $bJoseph Rudyard
499 __ $aKipling, Joseph Rudyard
640 1_ $dMumbai, India $f30/12/1865
640 2_ $dLondra, Marea Britanie $f18/01/1936
940 __ $abritanică